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AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper
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© examsnet.com
Question : 36
Total: 160
The coefficient of variation and standard deviation of an ungrouped data are 60 and 21 respectively. If 15 is added to every observation of the data, then the coefficient of variation of the new data is
30
42
40
20
Validate
Solution:
The expression for the coefficient of variance is given by,
C
V
=
σ
µ
×
100
Therefore,
60
=
21
µ
×
100
µ
=
21
×
10
6
=
35
The new mean on addition of 15 to every observation is,
µ
′
=
35
+
15
=
50
But
∑
|
µ
′
−
x
i
′
|
=
∑
|
µ
−
x
i
|
Now
21
=
√
∑
(
µ
−
x
i
)
2
n
21
2
=
∑
(
µ
−
x
i
)
2
n
∑
(
µ
−
x
i
)
2
=
21
2
×
n
Thus,
σ
′
=
√
∑
(
µ
′
−
x
i
′
)
2
n
=
√
21
2
×
n
n
=
21
Therefore, the new coefficient of variance is
C
V
New
=
21
50
×
100
=
42
© examsnet.com
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