Consider the given equation. √(x−2)2+y2+√(x+2)2+y2=4 Sum of the distance of point P(x,y) with respect to points A(2,0) and B(−2,0) is equal to the distance between the points A(2,0) and B(−2,0) AP+BP=AB Therefore, the locus of point P(x,y) is a line segment.