Consider the equation of curve, x2+xy+y2+x+3y+1=0 The equation of line joining the origin to the point of intersection of curve and the line is calculated as, x2+xy+y2+(x+3y)(
x+y
−2
)+(
x+y
−2
)2=0 x2+y2+xy−
1
2
(x2+4xy+3y2)+
1
4
(x2+2xy+y2)=0 3x2−2xy−y2=0 The equation of the bisector of the angle between the pair of straight line is,