AP EAMCET Engineering 2011 Solved Paper

Let V be the potential across the capacitor when it is fully charged, then, energy stored in the capacitor will be =

1

2

CV2
(where C= capacitance of capacitor )
When the capacitor is fully discharged, loss of energy is in the form of heat =ΔH
As the system is thermally isolated so,
ΔH=

1

2

CV2
Here, ΔH=msΔT
∴

1

2

CV2=msΔT
or V=(

2msΔT

C

)1∕2