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AP EAMCET Engineering 2011 Solved Paper
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© examsnet.com
Question : 57
Total: 160
The
p
H
of
0.05
M
acetic acid is
(
K
a
=
2
×
10
−
5
)
2
11
10
−
3
3
Validate
Solution:
C
H
3
C
O
O
H
⇌
H
+
+
C
H
3
C
O
O
−
K
a
=
[
H
+
]
[
C
H
3
C
O
O
−
]
[
C
H
3
C
O
O
H
]
=
[
H
+
]
2
[
C
H
3
C
O
O
H
]
[
H
+
]
=
√
K
a
[
C
H
3
C
O
O
H
]
=
√
2
×
10
−
5
×
0.05
=
√
10
−
6
[
H
+
]
=
10
−
3
∵
p
H
=
−
log
[
H
+
]
=
−
log
[
10
−
3
]
∴
p
H
=
3
© examsnet.com
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