AP EAMCET Engineering 2012 Solved Paper

There are two cases arise.
Case I When 5 questions are selected from first 6 questions and next 5 questions are selected from 7 questions.
∴ Number of ways =‌6C5×‌7C5
=6×

7×6

2×1

=126
Case III When 6 questions are selected from first 6 questions and next 4 questions are selected from 7 questions.
∴ Number of ways =‌6C6×‌7C4
=1×

7×6×5

3×2

=35
∴ Required number of ways =126+35=161