Given equation is |x|6∕5−26|x|3∕5−27=0 Put |x|3∕5=t ∴ t2−26t−27=0 ⇒ t2−27t+t−27=0 ⇒ t(t−27)+1(t−27)=0 ⇒ (t+1)(t−27)=0 ⇒ t=27 or −1 (∵|x|3∕5. can not be negative) ⇒ |x|3=(33)5 ⇒ |x|=35 ⇒ x=35 or −35 ∴Product of x=35×(−3)5=−310