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AP EAMCET Engineering 2012 Solved Paper
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© examsnet.com
Question : 13
Total: 160
A long curved conductor carries a current
I
(I is a vector). A small current element of length
d
l
, on the wire induces a magnetic field at a point, away from the current element. If the position vector between the current element and the point is
r
, making an angle with current element then, the induced magnetic field density;
d
B
(vector) at the point is
(
µ
0
=
permeability of free space
)
µ
0
Id
l
×
r
4
π
r
(perpendicular to the current element
d
l
)
µ
0
I
×
r
×
d
l
4
π
r
2
(perpendicular to the current element
d
l
)
µ
0
I
×
d
l
r
(perpendicular to the plane containing the current element and position vector
r
)
µ
0
I
×
d
l
4
π
r
2
(perpendicular to the plane containing current element and position vector
r
)
Validate
Solution:
The magnetic field
d
B
=
µ
0
I
×
r
×
d
l
4
π
r
2
© examsnet.com
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