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AP EAMCET Engineering 2012 Solved Paper
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© examsnet.com
Question : 36
Total: 160
A straight conductor of length
4
m
moves at a speed of
10
m
∕
s
. When the conductor makes on angle of
30
°
with the direction of magnetic field of induction of
0.1
W
b
−
m
2
, then induced emf is
8
V
4
V
1
V
2
V
Validate
Solution:
Induced emf is given by
e
=
B
v
l
sin
θ
=
0.1
×
10
<
4
sin
30
=
2
V
© examsnet.com
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