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AP EAMCET Engineering 2013 Solved Paper
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© examsnet.com
Question : 101
Total: 160
If
(
1
+
i
)
x
−
i
2
+
i
+
(
1
+
2
i
)
y
+
i
2
−
i
=
1
, then
(
x
,
y
)
isequal to
(
7
3
,
−
7
15
)
(
7
3
,
7
15
)
(
7
5
,
−
7
15
)
(
7
5
,
7
15
)
Validate
Solution:
(
1
+
i
)
x
−
i
2
+
i
+
(
1
+
2
i
)
y
+
i
2
−
i
=
1
⇒
[
(
1
+
i
)
x
−
i
]
(
2
−
i
)
(
4
−
i
2
)
+
[
(
1
+
2
i
)
y
+
i
]
(
2
+
i
)
(
4
−
i
2
)
=
1
⇒
2
(
1
+
i
)
x
−
2
i
−
i
(
1
+
i
)
x
+
i
2
4
+
1
+
2
(
1
+
2
i
)
y
+
2
i
+
i
(
1
+
2
i
)
y
+
i
2
(
4
+
1
)
=
1
⇒
(
2
+
2
i
−
i
−
i
2
)
x
−
2
i
+
i
2
5
+
(
4
i
+
2
+
i
+
2
i
2
)
y
+
2
i
+
i
2
5
=
1
⇒
(
2
+
i
+
1
)
x
−
2
i
−
1
5
+
(
5
i
+
2
−
2
)
y
+
2
i
−
1
5
=
1
⇒
(
3
+
i
)
x
−
2
i
−
1
+
(
5
i
)
y
+
2
i
−
1
=
5
⇒
(
3
+
i
)
x
+
5
i
y
=
7
⇒
3
x
+
i
x
+
5
i
y
−
7
=
0
⇒
(
3
x
−
7
)
+
(
x
+
5
y
)
i
=
0
+
i
0
On comparing, we get
3
x
−
7
=
0
⇒
x
=
7
3
and
x
+
5
y
=
0
⇒
y
=
−
7
15
Hence,
(
x
,
y
)
=
(
7
3
,
−
7
15
)
© examsnet.com
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