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AP EAMCET Engineering 2013 Solved Paper
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© examsnet.com
Question : 12
Total: 160
Two particles
A
and
B
of masses '
m
' and
2
m
' are suspended from massless springs of force constants
K
1
and
K
2
.
During their oscillation, if their maximum velocities are equal, then the ratio of amplitudes of
A
and
B
is
√
K
1
K
2
√
K
2
2
K
1
√
K
2
K
1
√
2
K
1
K
2
Validate
Solution:
We knows, maximum velocity
V
max
=
A
ω
=
A
√
K
m
Given,
K
1
,
m
1
=
m
,
K
2
,
m
2
=
2
m
(
V
max
)
A
=
(
V
max
)
B
A
A
√
K
1
M
=
A
B
√
K
2
2
m
⇒
A
A
A
B
=
√
K
2
2
K
1
© examsnet.com
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