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AP EAMCET Engineering 2014 Code A Solved Paper
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© examsnet.com
Question : 3
Total: 160
2
n
+
1
∑
k
=
1
(
−
1
)
k
−
1
.
k
2
(
n
+
1
)
(
2
n
+
1
)
(
n
+
1
)
(
2
n
−
1
)
(
n
−
1
)
(
2
n
+
1
)
(
n
−
1
)
(
2
n
−
1
)
Validate
Solution:
3
∑
k
=
1
(
−
1
)
k
−
1
k
−
2
=
1
+
(
−
1
)
2
−
1
(
4
)
+
(
−
1
)
3
−
1
3
2
=
1
−
4
+
9
=
6
2.3
=
6
© examsnet.com
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