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AP EAMCET Engineering 2015 Code C Paper
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Section:
Physics
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Ā© examsnet.com
Question : 107
Total: 160
A ball āPā moving with a speed of
n
m
s
ā
1
collides directly with another identical ball 'Q ' moving with a speed
10
m
s
ā
1
in the opposite direction. P comes to rest after the collision. If the coefficientof restitution is 0.6, the value of n is
30
m
s
ā
1
40
m
s
ā
1
50
m
s
ā
1
60
m
s
ā
1
Validate
Solution:
In inelastic collision of 2 bodies velocity of first body after collision is
v
1
V
1
=
v
1
(
m
1
ā
e
m
2
m
1
+
m
2
)
+
u
2
(
(
1
+
e
)
m
2
m
1
+
m
2
)
u
1
=
u
1
;
m
1
=
m
2
=
m
;
u
2
=
ā
10
m
s
ā
1
e
=
0.6
v
1
=
0
0
=
v
(
m
ā
0.6
m
m
+
m
)
ā
10
(
1
+
0.6
)
m
(
m
+
m
)
0
=
0.4
2
v
0.4
v
2
=
8
ā
v
=
16
0.4
v
=
40
m
s
ā
1
Ā© examsnet.com
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