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AP EAMCET Engineering 2015 Code C Paper
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© examsnet.com
Question : 93
Total: 160
In an AC circuit V and I are given below, then find the power dissipated in the circuit
V
=
50
sin
(
50
t
+
π
3
)
m
A
I
=
50
s
i
n
(
50
t
+
π
3
)
m
A
0.625
W
1.25
W
2.50
W
5.0
W
Validate
Solution:
Power=
V
rms
i
rms
c
o
s
ϕ
=
V
0
i
0
2
×
c
o
s
ϕ
=
50
×
50
2
×
c
o
s
(
π
3
)
mW
=
2500
2
×
1
2
×
10
−
3
W
=
2.5
4
W
P
=
0.625
W
© examsnet.com
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