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AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper
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© examsnet.com
Question : 109
Total: 160
A battery of emf 10 V is connected to a uniform wire AB of 1 m length and having a resistance of 10 Ω in series with a 10 Ω resistor as shown in the figure. Two cells of emf 2 V and 3 V having internal resistances 2 Ω and 3 Ω respectively are connected as shown in the figure.If the galvanometer shows null deflection at point J on the wire, die distance of point J from the point B is_______
48 cm
50 cm
52 cm
54 cm
Validate
Solution:
Consider the figure shown below,
The voltage drop in the wire is given as,
V
′
=
V
(
r
+
R
)
×
R
V
′
=
10
20
×
10
=
5
The potential gradient on wire is,
x
=
V
′
L
=
5
100
V
∕
cm
The effective emf in secondary circuit is given as,
1
r
eff
=
1
r
1
+
1
r
2
1
r
eff
=
1
2
+
1
3
=
5
6
V
=
6
5
(
1
+
1
)
=
12
5
The effective length from point A is given as,
l
=
V
x
=
12
5
×
100
5
l
=
48
cm
The length from point
B
comes out to be,
l
0
=
(
100
−
48
)
cm
=
52
cm
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