Test Index

AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

Question : 36

Total: 160

xi	6	9	3	12	15	13	21	22
fi	4	5	3	2	5	4	4	3

xi	fi	Cumulativefrequency	di=\|xi−15\|	fidi
6	4	4	9	36
9	5	9	6	30
3	3	12	12	36
12	2	14	3	6
15	5	19	0	0
13	4	23	2	8
21	4	27	6	24
22	3	30	7	21
	N=∑fi N=30			∑fidi=161

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