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AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper
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© examsnet.com
Question : 102
Total: 160
As shown in the figure, a parallel beam of light incident on the upper part of a prism of angle 1.8° and material of refractive index 1.5. The light immerging out from the prism falls on a concave mirror of radius of curvature 40 cm. The distance of the point from the principle axis of the mirror where the light rays are focussed after reflection from the mirror is
4.76 cm
1.57 cm
3.14 cm
6.28 cm
Validate
Solution:
The parallel beam is deviated by prism by angle,
δ
=
(
µ
−
1
)
A
=
(
1.5
−
1
)
(
1.8
°
)
=
(
0.9
°
)
(
π
180
°
)
radian
This beam from prism is also parallel and is conserved at a point in focal plane by concave mirror.
So, the distance is,
x
=
F
×
δ
=
R
2
×
δ
=
20
2
(
0.9
°
)
(
π
180
°
)
x
=
0.157
cm
=
1.57
cm
© examsnet.com
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