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AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper
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© examsnet.com
Question : 6
Total: 160
The system of equations
x
−
2
y
+
3
z
=
5
,
2
x
−
2
y
+
z
=
0
,
−
x
+
2
y
−
3
z
=
6
has
infinitely many solutions
exactly two solutions
unique solution
no solution
Validate
Solution:
Given equation,
x
−
2
y
+
3
z
=
5
2
x
−
2
y
+
z
=
0
−
x
+
2
y
−
3
z
=
6
The determinant is,
Δ
=
|
1
−
2
3
2
−
2
1
−
1
2
−
3
|
=
1
(
6
−
2
)
+
2
(
−
6
+
1
)
+
3
(
4
−
2
)
=
0
Δ
1
=
|
5
−
2
3
0
−
2
1
6
2
−
3
|
=
5
(
6
−
2
)
+
2
(
0
−
6
)
+
3
(
0
−
12
)
≠
0
Thus, the system has no solution.
© examsnet.com
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