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AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper
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© examsnet.com
Question : 94
Total: 160
A spherical body of density ρ is floating half immersed in a liquid of density d . If σ is the surface tension of the liquid, then the diameter of the body is
√
3
σ
g
(
2
ρ
−
d
)
√
6
σ
g
(
2
ρ
−
d
)
√
4
σ
g
(
2
ρ
−
d
)
√
12
σ
g
(
2
ρ
−
d
)
Validate
Solution:
The following figure represents the required diagram.
Write the expression of the weight of the body by using the diagram.
Weight of the body = Buoyant force + Force due to surface tension
4
3
π
r
3
ρ
g
=
2
3
π
r
3
d
g
+
2
π
r
σ
2
3
π
r
3
(
2
ρ
−
d
)
=
2
π
r
σ
r
2
=
3
σ
g
(
2
ρ
−
d
)
r
=
√
3
σ
g
(
2
ρ
−
d
)
© examsnet.com
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