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AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper
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© examsnet.com
Question : 130
Total: 160
If the ionization constant of hypochlorous acid (HOCl) is
2.5
×
10
−
5
, the pH of 1.0 M of its solution is ( log 5 = 0.7)
3.3
2.3
4.3
3.0
Validate
Solution:
First, we will calculate degree of ionization as follows:
α
=
√
K
a
C
=
√
2.5
×
10
−
5
1
=
5
×
10
−
3
The dissociation of HCl is shown below:
HOC
→
[
H
+
]
+
[
OCl
−
]
Initial
concentration
1
0
0
Final
0
α
α
The concentration of H
+
ions is equal to
α
=
5
×
10
−
3
.
The pH of solution can be calculated as :
p
H
=
−
log
[
H
+
]
=
−
log
(
5
×
10
−
3
)
=
2.3
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