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AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper
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© examsnet.com
Question : 99
Total: 160
The rms speed of oxygen molecule at a certain temperature is 600 ms
–
1
. If the temperature is doubled and oxygen molecules dissociates into atomic oxygen atoms, the new rms speed is
120 ms
–
1
150 ms
–
1
1200 ms
–
1
600 ms
–
1
Validate
Solution:
The expression of the rms velocity is,
v
rms
=
√
3
R
T
M
For temperature
T
1
, the rms velocity is,
600
=
√
3
R
T
1
M
...... (I)
For temperature
T
2
, the rms velocity is,
v
′
rms
=
√
3
R
(
2
T
1
)
(
M
∕
2
)
v
′
rms
=
2
√
3
R
T
1
M
...... (II)
v
′
rms
=
2
v
rms
v
′
rms
=
2
(
600
)
v
′
rms
=
1200
ms
−
1
© examsnet.com
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