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AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper
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© examsnet.com
Question : 36
Total: 160
Consider the frequency distribution
C.I.
75 - 175
175 - 275
275 - 375
375 - 475
475 - 575
575 - 675
675 - 775
f
i
3
2
1
0
1
2
3
If the variance of this distribution is 60000, then the coefficient of variation of the distribution is
60
400
√
6
17
400
√
6
9
595.75
Validate
Solution:
By using the given data
CI
f
i
Mid-Value
x
i
f
i
x
i
75-175
3
125
375
75-175
2
225
450
275-375
1
325
325
375-475
0
425
0
475-575
1
525
525
575-675
2
625
1250
675-775
4
725
2175
∑
f
i
=
12
∑
f
i
x
i
=
5100
The mean of the data is
X
=
∑
f
i
x
i
∑
f
i
=
5100
12
=
425
The coefficient of variation is
C
V
=
σ
X
×
100
=
100
√
6
425
×
100
=
400
√
6
17
© examsnet.com
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