Consider the given data, In triangle AOC tan‌60∘=‌
x
y
√3=‌
x
y
The diagram of triangle is,
From the above figure, x‌‌=√3y x+y‌‌=2(√3+1) y(√3+1)‌‌=2(√3+1) y‌‌=2 So x=2√3 Now area‌of∆ABC=area‌of△AOB+area‌of△AOC =‌