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AP EAMCET Engineering 21 Apr 2019 Shift 1 Paper
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© examsnet.com
Question : 36
Total: 160
The mean deviation about the mean for the following data is
Class interval
0 - 10
10 - 20
20 - 30
30 - 40
40 - 50
50 - 60
60 - 70
Frequency
4
6
16
28
16
6
4
35
10
15
12
Validate
Solution:
Class Interval
f
i
x
i
f
i
x
i
|
x
i
−
35
|
f
i
x
i
−
35
|
0-10
4
5
20
30
120
10-20
6
15
90
20
120
20-30
16
25
400
10
160
30-40
28
35
980
0
0
40-50
16
45
720
10
160
50-60
6
55
33
20
120
60-70
4
65
260
30
120
Total
80
2800
800
The mean is
X
=
∑
f
i
x
i
∑
f
i
=
2800
80
=
35
The mean deviation is calculated as,
M
⋅
D
=
1
N
n
∑
i
=
1
f
i
|
x
i
−
x
|
=
1
80
n
∑
i
=
1
f
i
|
x
i
−
35
|
=
1
80
(
800
)
=
10
© examsnet.com
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