Consider the equation of perpendicular bisector is y=mx+c The intercept is 1, thus the equation becomes y=mx+1 The mid-point of the points A(α,3) and B(2,−1) is (
α+2
2
,1) since the equation passes through (
α+2
2
,1) Thus, 1=m(
α+2
2
)+1 2=m(α+2)+2 m(α+2)=0 mα+2m=0⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅(I) Here, m is the gradient of the perpendicular line. m=−(