(c) According to question, speed of the centre of wheel is v0.
Particle is situated on the rim of wheel as shown in Fig. (ii). ∴‌‌v=rω‌=√(OP)2+(OM)2⋅ω=√R2+R2⋅ω v‌=√2Rω‌‌(i) ‌ But ‌‌‌v0‌=Rω‌‌(ii) From Eqs. (i) and (ii), we get v=√2v0