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AP EAMCET Engineering 21 Sep 2020 Shift 2 Paper
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© examsnet.com
Question : 2
Total: 160
The locus of
z
satisfying
|
z
−
i
z
−
2
i
|
=
2
is a
Hyperbola
Circle
Straight line
Ellipse
Validate
Solution:
(b) It is given that,
|
z
−
i
z
−
2
i
|
=
2
Let
z
=
x
+
i
y
, then
|
x
+
i
(
y
−
1
)
|
=
2
|
x
+
(
y
−
2
)
i
|
⇒
x
2
+
(
y
−
1
)
2
=
4
[
x
2
+
(
y
−
2
)
2
]
⇒
3
x
2
+
3
y
2
−
14
y
+
16
=
0
represent a circle,
so locus of
z
is a circle.
© examsnet.com
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