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AP EAMCET Engineering 21 Sep 2020 Shift 2 Paper
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Section:
Physics
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© examsnet.com
Question : 81
Total: 160
A body executes simple harmonic motion with an amplitude
A
. At what displacement, from the mean position, is the potential energy of the body one fourth of its total energy?
A
4
A
2
3
A
4
3
A
Validate
Solution:
(b) According to question,
In simple harmonic motion, potential energy
=
‌
1
4
(total energy)
⇒
‌
1
2
m
ω
2
y
2
=
‌
1
4
[
‌
1
2
m
ω
2
A
2
]
⇒
y
2
=
‌
A
2
4
⇒
y
=
‌
A
2
© examsnet.com
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