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AP EAMCET Engineering 22 Sep 2020 Shift 1 Paper
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© examsnet.com
Question : 59
Total: 160
For
f
(
x
)
=
sin
(
1
|
x
|
√
x
2
−
1
)
the domain and range of
f
(
x
)
in
R
are
R
−
{
0
,
±
1
} and
[
−
1
,
1
]
, respectively
R
−
{
−
1
,
1
} and
[
−
1
,
1
]
, respectively
R
−
{
0
,
±
1
} and
[
0
,
1
]
, respectively
R
−
{
−
1
,
1
} and
[
0
,
1
]
, respectively
Validate
Solution:
Given function
f
(
x
)
=
sin
(
1
|
x
|
√
x
2
−
1
)
For the domain,
|
x
|
≠
0
⇒
x
≠
0
and
x
2
−
1
>
0
⇒
x
∈
R
−
[
−
1
,
1
]
So domain of
f
is
R
−
[
−
1
,
1
]
and we know the range of sine function is
[
−
1
,
1
]
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