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AP EAMCET Engineering 22 Sep 2020 Shift 1 Paper
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© examsnet.com
Question : 95
Total: 160
A travelling microscope is focused on an ink dot marked on a piece of paper. When a glass slab
(
µ
=
1.5
)
of thickness
0.12
m
is placed on the ink dot. The travelling microscope has to be moved__________ in order to restore the focus.
0.04
m
downwards
0.04
m
upwards
0.06
m
downwards
0.06
m
upwards
Validate
Solution:
We know that,
Refractive index,
µ
=
Real depth
Apparent depth
Here,
µ
=
1.5
and real depth = thickness of glass
slab
=
0.12
m
∴
µ
=
0.12
Apparent depth
Apparent depth
=
0.12
1.5
=
0.08
m
Hence, image appears to be raised by
0.08
2
m
=
0.04
m
Hence, travelling microscope must be moved upward by
0.04
m
.
© examsnet.com
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