P=(−1,3,−2) Let dr's or required line be (a,b,c) Dr's of line ‌
x
1
=‌
y
2
=‌
z
3
are (1,2,3) Given that required line perpendicular to above line ⇒‌‌a1a2+b1b2+c1c2=0 ⇒‌‌a+2b+3c=0...(i) Similarly required line perpendicular to ‌
x+2
−3
=‌
y−1
2
=‌
z+1
5
⇒‌‌−3a+2b+5c=0 ...(ii) On solving Eqs. (i) and (ii), we get ‌
a
10−6
=‌
b
−9−5
=‌
c
2+6
⇒‌‌‌
a
2
=‌
b
−7
=‌
c
4
∴ Required line is passing through (−1,3,−2) and having dr's (2,−7,4) ∴‌‌‌