Consider the expression, (1−x)(1−2x)(1−3x)1​=(1−x)−1(1−2x)−1(1−3x)−1=(1+x+x2+x3+x4)(1+2x+4x2+8x3+16x4)(1+3x+9x2+27x3+81x4) The coefficient of x4 is required so expand up to x4, (1−ax)−n=1+ax+a2x2+a3x3+. So, coefficient of x4 is, 81+54+36+24+16+27+18+12+8+9+4+3+2+1=301