Consider the integral, I(x)=∫e2x(cos(3x+4)+5x2)dx=∫e2xcos(3x+4)dx+5∫e2xx2dx=e2x[132cos(3x+4)+133sin(3x+4)]+25x2e2x−5∫xe2xdx=e2x(132cos(3x+4)+133sin(3x+4))+25x2e2x−25xe2x+25∫e2xdx Further simplify the above, =e2x(132cos(3x+4)+133sin(3x+4))+25x2e2x−25xe2x+45e2x
e2x[132cos(3x+4)+133sin(3x+4)+25x2−25x+45] + c