Given Data: u=5m∕s a=−10m∕s2 h=−30m The figure below represents the projectile motion.
h=ut+
1
2
at2 −30=5t−
1
2
×10×t2 By solving the above equation. t=3 or t≠−2 t=3s The distance covered in east direction is, dx=3×3=9m The distance covered in north direction is, dy=4×3=12m