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AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper
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Section:
Physics
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© examsnet.com
Question : 88
Total: 160
Two blocks of masses ‘M’ and ‘nV are placed on one another on a smooth horizontal surface as shown in the figure. The force T' is acting on the mass ‘M’ horizontally during time interval ‘V. Assuming no relative sliding between the blocks, the work done by friction onthe blocks is _________
mF
2
t
2
2
(
M
+
m
)
2
F
2
t
2
(
M
+
m
)
M
+
m
mt
2
F
t
2
(
M
+
m
)
Validate
Solution:
The acceleration of the block can be calculated as,
F
=
(
m
+
M
)
a
a
=
F
m
+
M
since there is no relative sliding, the frictional force on upper block is,
f
=
m
a
f
=
m
(
F
M
+
m
)
The distance covered can be calculated as,
D
=
1
2
a
t
2
D
=
1
2
(
F
M
+
m
)
t
2
The work done by the frictional force is,
W
=
f
×
s
=
m
F
M
+
m
×
1
2
F
t
2
m
+
m
=
m
F
2
t
2
2
(
m
+
M
)
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