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AP EAMCET Engineering 26 Apr 2017 Shift 1 Paper
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© examsnet.com
Question : 96
Total: 160
A wall is made of equally thick layers ‘P' and 'Q' of different materials. Thermal conductivity of ‘Q’ is half of that of the ‘P’. In the steady state, if the temperature difference across the wall is 24 °C. then the temperature difference across the layer 'P' is_________
12 °C
8 °C
16 °C
4 °C
Validate
Solution:
The figure below represents the wall
P
and
Q
.
It is given that,
k
Q
=
k
p
2
k
p
=
2
k
Q
And
T
1
−
T
2
=
24
°
C
In steady state, the rate of flow heat through layer
P
and
Q
issame,
k
p
a
(
T
1
−
T
3
)
x
=
k
Q
a
(
T
3
−
T
2
)
x
Substitute the values in the above equation.
2
k
Q
a
(
T
1
−
T
3
)
x
=
k
Q
a
(
T
3
−
T
2
)
x
2
(
T
1
−
T
3
)
=
(
T
3
−
T
2
)
2
T
1
−
3
T
3
+
T
2
=
0
From equation (I),
2
T
1
−
3
T
3
+
T
1
−
24
=
0
3
T
1
−
3
T
0
=
24
T
1
−
T
0
=
8
°
C
© examsnet.com
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