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AP EAPCET 04-Jul-2022 Shift 1 Paper
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© examsnet.com
Question : 67
Total: 160
The maximum value of
f
(
x
)
=
x
1
+
4
x
+
x
2
is
1
4
1
5
1
6
1
7
Validate
Solution:
👈: Video Solution
f
(
x
)
=
x
1
+
4
x
+
x
2
f
′
(
x
)
=
(
1
+
4
x
+
x
2
)
(
1
)
−
x
(
4
+
2
x
)
(
1
+
4
x
+
x
2
)
2
=
1
−
x
2
(
1
+
4
x
+
x
2
)
2
Put
f
′
(
x
)
=
0
⇒
x
=
±
1
At
x
=
−
1
, it gives minimum value.
At
x
=
1
, it gives maximum value.
Put
x
=
1
in
f
(
x
)
, we get
f
(
1
)
=
1
1
+
4
+
1
=
1
6
© examsnet.com
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