‌‌ where ‌θ=30∘ If PA=r1,PB=r2 then r1,r2 are the roots of the equation, (2+r‌cos‌θ)2−2(2+r‌cos‌θ)⋅(3+rsin‌θ)−(3+rsin‌θ)2=0 ‌⇒r2(cos‌2‌θ−sin‌2θ)−2r(cos‌θ+5sin‌θ)−17=0 ‌‌ So, ‌PA⋅PB=r1r2=‌