From Newton's law, ΣF= ma Force on M1, in x-direction, T=M1a........(i). in y-direction, N1−w1=0......(ii) Similarly, forces on M2, in x-direction, M2gsin‌θ−T=M2a...(iii) in y-direction, N2−m2g‌cos‌θ=0...(iv) Adding to eq. (i) with eq. (ii), we get M2gsin‌θ‌=M1a+M2a ⇒‌‌a‌=‌
M2gsin‌θ
M1+M2
According to question, when M1 is doubled and M2 is halved a′=‌