The magnetic field in a plane electromagnetic wave is given \overline{ {B}}=(3 \times 10^{-7} {T}) \sin (3 \times 10^{4} x+9 \times 10^{12} {t}) \hat{ {j} The electric field of this wave is given as

Correct Answer is : 90sin(3×104x+9×1012t)∧kVm−1

90 \sin (3 \times 10^{4} x+9 \times 10^{12} {t}) \hat{ {i} {Vm}^{-1}

90 \sin (3 \times 10^{4} x+9 \times 10^{12} {t}) \hat{ {k} {Vm}^{-1}

245 \sin (3 \times 10^{4} x+9 \times 10^{12} {t}) \hat{ {i} {Vm}^{-1}

255 \sin (3 \times 10^{4} x+9 \times 10^{12} {t}) \hat{ {k} {Vm}^{-1}

Test Index

AP EAPCET 05-Jul-2022 Shift 1 Paper

Section: Physics

Question : 114

Total: 160

The electric field of this wave is given as

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