We know that, the radius (R) of nucleus is given as R=R0A1/3 or R∝A1/3 Where,R0=constantA=mass number∴ Nuclear density, ρ=volumemass=34πR3mA (here, m is mass of each nucleon) ⇒ρ=34π(R0A1/3)3mA=34πR03AmAρ=4πR033m Hence, it is clear from above formula, nuclear density is independent of mass number A.The binding energy, E=Δmc2i. e E∝ΔmWhere, Δm= mass defectEnergy is released when heavy nuclei undergo transmutation into light nuclei.