The two vectors A and B are mutually perpendicular to each other ‌‌ A. B ‌=0. ⇒AB‌cos‌θ=0 ⇒cos‌θ=0⇒θ=90∘ |A−B|‌ ‌=√A2+B2−2AB‌cos‌90∘ ‌=√A2+B2 Unit vector along A−B =‌
A−B
|A−B|
=‌
A−B
√A2+B2
component of (A+B) in direction of (A−B) will be given as, ‌=‌