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AP EAPCET 06-Jul-2022 Shift 1 Paper
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© examsnet.com
Question : 39
Total: 160
The random variable
X
has Binomial distribution
B
(
20
,
0.4
)
. Then
5
−
5
P
(
X
≥
2
)
=
62
(
2
5
)
19
43
(
3
5
)
19
1
+
23
(
3
19
5
20
)
1
+
62
(
2
19
5
20
)
Validate
Solution:
👈: Video Solution
We have,
n
=
20
,
p
=
0.4
,
q
=
0.6
Then,
5
−
5
P
(
X
≥
2
)
=
5
[
1
−
P
(
X
≥
2
)
]
=
5
[
P
(
X
<
2
)
=
5
[
P
(
X
=
0
)
+
P
(
X
=
1
)
]
=
5
[
20
C
0
(
0.4
)
0
(
0.6
)
20
+
20
C
1
(
0.4
)
(
0.6
)
19
]
=
5
[
(
3
5
)
20
+
20
×
2
5
×
(
3
5
)
19
]
=
5
×
(
3
5
)
19
[
3
5
+
8
]
.
=
5
×
(
3
5
)
19
⋅
[
43
5
]
=
43
(
3
5
)
19
© examsnet.com
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