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AP EAPCET 06-Jul-2022 Shift 2 Paper
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© examsnet.com
Question : 4
Total: 160
If the system of simultaneous linear equations
3
x
−
4
y
+
k
z
+
13
=
0
,
x
+
2
y
−
z
−
9
=
0
and
k
x
−
y
+
3
z
+
7
=
0
has a unique solution
x
=
α
,
y
=
β
,
z
=
γ
for
k
≠
m
and
2
β
−
γ
=
8
then
α
+
m
=
20
8
5
29
None of the above
Validate
Solution:
👈: Video Solution
|
3
−
4
k
1
2
−
1
k
−
1
3
|
≠
0
⇒
3
(
6
−
1
)
+
4
(
3
+
k
)
+
k
(
−
1
−
2
k
)
≠
0
⇒
15
+
12
+
4
k
−
k
−
2
k
2
≠
0
⇒
2
k
2
−
3
k
−
27
≠
0
⇒
2
k
2
−
9
k
+
6
k
−
27
≠
0
⇒
k
≠
9
2
,
−
3
On putting
x
=
α
,
y
=
β
,
z
=
γ
inequation
x
+
2
y
−
z
−
9
=
0
α
+
2
β
−
γ
−
9
=
0
α
+
8
−
9
=
0
[It is given that
2
β
−
γ
=
8
]
α
=
1
As
k
≠
m
⇒
m
=
9
∕
2
,
−
3
α
+
m
=
1
+
9
2
=
11
2
or
α
+
m
=
1
−
3
=
−
2
© examsnet.com
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