Given, mass of metal block, m=3.3‌kg Temperature, ∆T=400∘C Specific heat of metal block, sm=0.4Jg−1K−1 =400Jkg−1K−1 Latent heat of fusion, Lf=330Jg−1=3.3×105Jkg−1 If m′ be the maximum amount of mass of melted ice, then m′Lf‌=msm∆T ⇒‌‌m′‌=‌