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AP EAPCET 08-Jul-2022 Shift 1 Paper
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© examsnet.com
Question : 61
Total: 160
lim
x
→
0
x
2
log
(
cos
x
)
log
(
1
+
x
2
)
=
0
1
−
1
∞
Validate
Solution:
👈: Video Solution
lim
x
→
0
x
2
log
(
c
o
s
x
)
log
(
1
+
x
2
)
Apply L'hospital rule
lim
x
→
0
x
2
×
1
c
o
s
x
(
−
s
i
n
x
)
+
l
o
g
(
c
o
s
x
)
×
2
x
(
1
1
+
x
2
)
=
lim
x
→
0
(
1
+
x
2
)
[
−
x
2
t
a
n
x
+
2
x
l
o
g
c
o
s
x
]
Substitute
0
for
x
(
1
+
0
)
[
0
+
0
]
=
0
© examsnet.com
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