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AP EAPCET 17th May 2023 Shift 2 Solved Paper

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Question : 50

Total: 160

Let the locus of the point of intersection of the perpendicular tangents drawn to the circle x2+y2+6x−4y−12=0 be the circle S. Then the equation of the tangent drawn to S which is perpendicular to the line 6x−4y+k=0 is

24x+6y±√26=0
2x+3y±√26=0
2x+3y±5√26=0
4x+6y±5√26=0

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