Given the problem involves finding the value of (α+β+γ)2 when (α,β,γ) are the direction cosines of the angular bisector of two lines with direction ratios (2,2,1) and (2,−1,−2).Finding Direction Cosines:The direction ratios for line L1 are (2,2,1), and for line L2 are (2,−1,−2).The direction cosines for L1 are found as:(32,32,31)Similarly, for L2 the direction cosines are:(32,3−1,3−2)Perpendicular Check:The dot product of the two direction ratios confirms that the lines are perpendicular:2×2+2×(−1)+1×(−2)=0Angle Bisector Direction Cosines:The formulas for the direction cosines of the angle bisectors are:(2cos2θl1+l2,2cos2θm1+m2,2cos2θn1+n2)and(2sin2θl1−l2,2sin2θm1−m2,2sin2θn1−n2)Calculate the Direction Cosines:For an angle bisector direction, calculate:(324,321,32−1)Another possible set is:(0,21,21)Calculation of (α+β+γ)2 :Using α=324,β=321,γ=32−1 :Sum:α+β+γ=324+321−321=324(α+β+γ)2=(324)2=1816=98Alternatively, use α=0,β=21,γ=21 :Sum:α+β+γ=0+21+21=2Squaring:(α+β+γ)2=(2)2=2Based on calculations with valid assumptions, the value of (α+β+γ)2 considering a correct scenario for calculation comes out to be 2 .