Spring constant, k=5×103N∕m Initially stretched position, x1=10cm=0.1m Further stretched position, x2=20cm=0.2m Work Done: The work done to further stretch the spring from x1 to x2 is equal to the change in potential energy of the spring. This can be calculated using the formula: ‌ Work done ‌=‌
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k[(x2)2−(x1)2] Substitute the given values: ‌=‌
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×5×103[(0.2)2−(0.1)2] ‌=‌
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×5×103×(0.04−0.01) ‌=‌
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×5×103×0.03 ‌=2.5×103×0.03 ‌=75N⋅m Therefore, the work required to stretch the spring further by another 10 cm is 75N⋅m.
