Given, coefficient of friction =µ Angle of inclination =θ Acceleration due to gravity =g
Now, from the free body diagram of inclined plane and mass system. Force along the plane, mgsinθ−f=ma Here,f=µN ⇒mgsinθ−µN=ma ...(i) and force along line perpendicular to plane will be N=mgcosθ ...(ii) where, m,f,a and N are mass, friction force, acceleration and normal reaction experienced by the body. Now, from Eqs. (i) and (ii), we get mgsinθ−µmgcosθ=ma ⇒a=g(sinθ−µcosθ)
